Discussion Physical chemistry exp 1 | Heat Capacity

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the objective of the experiment to investigate or study about heat loss
  Discussion Hess Law defines the heat of any reaction Δ  H for a specific reaction is equal to the sum of the heats of reaction for any set of reactions which in sum are equivalent to the overall reactions. In our case exothermic reaction is applied for this experiment involving three part or stages in obtaining Δ  H changes and study the reaction that involve in Hess Law.Before discussing the result from the experiment, the experimenter must understand first the definition of enthalpy change which is enthalpy change is the name given to the amount of heat released or absorbed in a reaction carried out at constant pressure which in our experiment we are more focusing or heat release. lso, in applying the formula for calculation in obtaining the result of Δ  H changes. !he formula used for this experiment is q = msΔT  # specific heat$ # massΔ T # !f % !i &'inal temperature % Initial temperature() # )pecific heat capacity of water, )water # *.+*-g/0!he reason for using the same amount of specific heat capacity of water, ) is even in different solution, there are still water present and even if there is a difference it will only be slightly different and other factors ignored and use the constant amount of specific heat capacity of water,) which is *.+*-g/0.  In better understanding of the stages which includes part  & )olid 1a2H 3 4istilled water ( , 5art B & 1a2H )olution 3 H0L )olution ( and 5art 0 & )olid 1a2H 3 H0L )olution (, the differences between 5art  is the reaction of solid with water resulting in the lowest temperature due to single reaction from solid 1a2H while for 5art B the temperature increase higher than 5art  due to reaction between both solution and lastly for 5art 0 which is the highest and the total of 5art  and 5art B is the reaction between solid 1a2H and H0L solution which ma6e it warmer than other reaction due to heat release from solid 1a2H into the H0L solution. ll of these experiment is due to specific heat contain in each solid and solution and the reaction  between it resulting in the temperature increase.Based upon the result from 5art , Δ  H is 78.++6-mol. !he temperature recorded is 97/0 for !i &Initial temperature( and :+/0 for !f &'inal temperature( the specific heat obtained should be slightly higher than the result calculated. 4ue to the variation of temperature might as well having the error in result. !he temperature plays important role in this experiment when calculating the heat released or absorbed the temperature should stay in range of the experiment needed.'or the second part which is 5art B, the same problem occurred in 5art  resulting in a slightly lower value than the value should be conserved. !he result after the calculation is applied is 99.;*6-mol when the !i is 97/0 meanwhile !f is :*/0. !his error may arise due to thermometer error, since thermometer might come from * main factor of instrument errors which is accuracy, range, response time and sensitivity which may suggest that the instruments is getting old.  !he last part which is part : or 5art 0, the result obtain is <;.=6-mol. !he result which should bethe sum or the total of 5art  and 5art B, from the Hess> Law theory stated that the heat of any reaction for a specific reaction is equal to the sum of the heats of reaction for any set of reactions which in sum are equivalent to the overall reactions. In other words the equation from the theory should be? Δ  H3 = Δ  H1 + Δ  H2 'or the result Δ  H3 = Δ  H1 + Δ  H2 Δ  H    + # 78.++6-molΔ  H2 = 99.;*6-molΔ  H3  # <;.=6-molΔ  H1 + Δ  H2 = <:.876-mol)ince the result of the experiment Δ  H3 is the total of Δ  H1 + Δ  H2 , the differences of the result from the right answer is % =.=76-mol considering all the errors discussed above. !o increase the accuracy of result for this experiment, it is suggested that the thermometer should be tested first  before starting the experiment to avoid further error in measuring the temperature which plays animportant role in obtaining the best results because in physical chemistry, accuracy and precisionis the vital part in having a good result of measurement.
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